![]() ![]() The Mustang II spindles are available in 7, 10 and 11 degrees of KPI. I've been trying to firm up choices of spindles on my project. Warren thanks for posting these formulas. ![]() The columns are cambers at various roll angles: 0,1,2. ![]() The first column of each table is steering lock: 0, 5, 10, 15 and 20 degrees. (My apologies for the unformatted Table, but I wanted to put it in the message body. Being a Naval Architect by profession, the only value in this table for which I have an intuitive appreciation is roll angle! So, the question is: for those of you who have done this before, do my resulting cambers for the outer wheel look reasonable? The inner wheel seems to be a dead loss, but that seems consistent with everything I’ve read. These values seem to be in the ballpark for Miata and Corvette according to ‘Steve’ in my earlier post where I reported his formulae. ![]() The calculations are based on 7 degrees of caster and 10.9 degrees of kingpin inclination. Following are the results of my string computer exercise, including the effects of steering lock, using the formulae for camber induced by caster and kingpin inclination according to my preceeding post. ![]()
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